6x^2+54x+112=4

Solution for 6x^2+54x+112=4 equation:

6x^2+54x+112=4

We move all terms to the left:

6x^2+54x+112-(4)=0

We add all the numbers together, and all the variables

6x^2+54x+108=0

a = 6; b = 54; c = +108;
Δ = b2-4ac
Δ = 542-4·6·108
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-18}{2*6}=\frac{-72}{12}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+18}{2*6}=\frac{-36}{12}
=-3
$